Question

2. Find the heat required to convert 20 g of ice at
0°C into water at the same temperature.
(Specific latent heat of fusion of ice = 80 cal/g)​

Answer 1

Answer:

Amount of heat required=latent heat of ice+heat required to convert water from 0

o

C to 40

o

C

=mL

i

+mcΔT

=5[80+1(40−0)]

=400+200=600cal