Question

2. Find the heat required to convert 20 g of ice at
0°C into water at the same temperature.
(Specific latent heat of fusion of ice = 80 cal/g)​

Answer 1

Answer:

Since ice melted at 0 Celesius then the heat gained by ice (latent heat) will melt it so you should substitute in that law

Q=mlf ..where Q is the heat required to convert ice to water , m is the mass of ice and lf is the latent heat of fusion

Q=5∗80=400cal

Explanation:

Ok