Question

2. Find the height of a trapezium, the sum of lengths of whose bases is 39 cm and whose area
is 65 cm²​

Answer 1

Step-by-step explanation:

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Answer 2

◉QuesTion◉

Find the height of a trapezium, the sum of lengths of whose bases is 39 cm and

whose area is 65 cm².

╬SoluTion:

Given,

Area of Trapezium = 65cm²

Sum of Lengths = 39cm → (a+b)

Let's, Height be 'h'

We know that

$\boxed{\sf{Area\;of\;Trapezium = \frac{(a+b)}{2}h}}$

➝ $\bf{\frac {(39)}{2}×h = 65}$

➝ $\bf{h = \frac {65×2}{39}}$

➝ $\bf{h = \frac {130}{39}}$

➝ $\boxed{\bf{h = 3.33cm}}$

$\pink{\underline{\underline{\bf{Required\;AnSweR:}}}}$

Height of Trapezium 'h' ☞ $\fbox\red{3.33cm}$

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