Question

2. Find the LCM and HCF of the following integers by the prime factorization method.
(i) 12, 15 and 21
(ji) 17,23, and 29 (iii) 8, 9 and 25
(iv) 72 and 108 (v) 306 and 657​

Answer 1

Answer:

Hey listen up. I'm running out of time so I'll answer only one of them

3|_ 12,15,21

2|_4,5,7

2|_2,5,7

5|_1,1,7

7|_1,1,1

So their HCF is gonna be 3 as it's the only number that could divide all of then in the above prime factorisation.

And their LCM is 3*2*2*5*7 is 420.

Hope it helps and pls mark me as ur brainliest answer as I want to proceed to the next level

Answer 2

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Using prime factorisation method:

(i) 12, 15 and 21

Factor of 12=2×2×3

Factor of 15=3×5

Factor of 21=3×7

HCF (12,15,21)=3

LCM (12,15,21)=2×2×3×5×7=420

(ii) 17, 23 and 29

Factor of 17=1×17

Factor of 23=1×23

Factor of 29=1×29

HCF (17,23,29)=1

LCM (17,23,29)=1×17×23×29=11,339

(iii) 8, 9 and 25

Factor of 8=2×2×2×1

Factor of 9=3×3×1

Factor of 25=5×5×1

HCF (8,9,25)=1

LCM (8,9,25)=2×2×2×3×3×5×5=1,800