2. Find the LCM and HCF of the following pairs of integers and verify that LCM X HCF
product of the two numbers.
(i) 26 and 91
(ii) 510 and 92
Answers
26 and 91
26 = 2 × 13
91 = 7 × 13
thus the HCF of 26 and 91 = 13
the LCM of 26 and 91 = 2×7×13
= 182
510 and 92
510 = 2×3×5×17
92. = 2×2×23
thus the HCF of the solution = 2
the LCM of the solution = 2×2×3×5×17×23
= 23,460
this is the ans of the solution please mark as a brainlist
Question
Find the LCM and HCF of the following pairs of integers and verify that LCM x HCF product of the two numbers.
(i) 26 and 91
(ii) 510 and 92
Solution
26 = 2¹ × 13¹
L.C.M = 2 × 13 × 7
= 14 × 13
= 182
91 = 7¹ × 13¹
H.C.F = 13 × 1
= 13
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Verification :-
L.C.M × H.C.F = Product of two numbers.
L.H.S = L.C.M × H.C.F
= 182 × 13
= 2366
R.H.S = 26 × 91
= 2366
L.H.S = R.H.S
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- 510 and 92
510 = 2¹ × 3¹ × 5¹ × 17¹
L.C.M = 2 × 3 × 5 × 17 × 23
= 23460
⠀⠀
92 = 2² × 23¹
H.C.F = 2 × 1 × 1 × 1 × 1
= 2
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Verification :-
L.C.M × H.C.F = Product of 2 number.
L.H.S = 23460 × 2
= 46920
R.H.S = 510 × 92
= 46920
R.H.S = L.H.S
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