Math, asked by Drishtimali, 1 month ago

2) Find the least number which when divided by 16, 20 and 24 leave a remainder 7 in
each case.

Answers

Answered by pcchaudhari1204

1

Answer:

12 = 2x2x3

16 = 2x2x2x2

24 = 2x2x2x3

36 = 2x2x3x3

LCM(12,16,24,36) = 2x2x2x2x3x3 = 144

Hence 144 +7 = 151 is divided by 12,16,24,36 leaves the reminder 7.

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Answered by chaudharipravin024

1

Answer:

the person who has given first answer is correct

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