Question

2. Find the lettered angles in each
case


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please answer ​

Answer 1

Step-by-step explanation:

I) At B 120°+y=180°

y=180-120=60

EXTERIOR ANGLE IS EQUAL TO OPPOSITE INTERIOR ANGLE

SO, Y=60°

X=60°

ii) AT A , 100°+Y= 180°

Y=180-100

Y=80°

In ∆ BAP,

Z=?

Z+100+50=180°

Z=180-150

Z=30°

In ∆ BCA, Y=80°

X+Y+75° = 180°

X+80°+75°=180°

X=180°-155°

X= 25°