Question

2. Find the lettered angles in each case with solutions :​

Answer 1

Answer:

(3) x= 70 , z=70, y=40

(1)y=60 , x=100

(2) z=30 ,y=80,x=25

(4) x=40

Step-by-step explanation:

(3) angle FAE = Angle x ( V.O.A)

So angle x= 70

Z +ACD = 180

Z +110=180

Z=180-110

Z=70

sum of all angles of a triangle are 180 ,so

x+y+z = 180

70+70+y=180

140+y=180

y=40

(1) y+120=180

y=60

40+60+ACB=180

ACB=80

ACE Is a straight line so

x + ACB =180

X+80=180

X=100

(2) In Triangle PBA

50 +100 +Z = 180

150+Z =180

Z=30

100+Y=180

Y=80

IN Triangle ABC

Y+75+X=180

80+75+X=180

155+X=180

X=25

(4) In Triangle ABC

50+90 + Angle ACB = 180

ACB =40

NOW IN Triangle EDC

100+40+X=180

x=40