Question

2) Find the mean of the following frequency distribution using Short Cut Method.
Class 0-50 50-100 100-150 150-200 200-250 | 250-300 frequency 4 8 16 13 6 3
interval
| Frequency 4 8 16 13 6 3​

Answer 1

Given :- Find the mean of the following frequency distribution using Short Cut Method.

Class 0-50 50-100 100-150 150-200 200-250 | 250-300 frequency 4 8 16 13 6 3

Solution :-

Class interval fi xi fixi

0 - 50 4 25 100

50 - 100 8 75 600

100 - 150 16 125 2000

150 - 200 13 175 2275

200 - 250 6 225 1350

250 - 300 3 275 825

Total ⅀fi = 50 ⅀fixi = 7150

So,

→ Mean = ⅀fixi / ⅀fi

→ Mean = 7150 / 50

→ Mean = 143 (Ans.)

Hence, mean of the following frequency distribution is 143.

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