Physics, asked by georgenancy765, 29 days ago

2. Find the minimum velocity with which a Stone in to be projected in order to hit a Target at 20m away?​

Answers

Answered by sandeepdas4bl
2

Answer:

7\sqrt{2} i + 7\sqrt{2} j m/s is the minimum velocity with which the stone should be profected

Explanation:

The formla for horizontal range is: R = \frac{u^{2}sin(2\theta)}{g}

where u is the speed of projection and θ is the angle of projection

Thus more maximum value of sin2θ we get the minimum value of u for a constant range.

in our case the range is 20m and the maximum value of sin2θ is 1 for θ= pi/4

so

\frac{u^{2} }{g} = 20

u= \sqrt{20g}

u= \sqrt{196}

u= 14m/s (minimum speed)

u= 7\sqrt{2} i + 7\sqrt{2} j (minimum velocity)

Thus we obtain the minimum speed and velocity.

Hope this helps!!!

Similar questions