Question

2.Find the nature of the roots of the quadratic equation 2x² -3x + 5 = 0. *
1 point
real roots
imaginary roots​

Answer 1

Answer:

2x^2-3x+5=0

2x^2+2x-5x+5=0

2x(x+1)-5(x-1)=0

2x-5=0 , (x+1)(x-1)=0

x=⁵/2 , x= 1 [x^2-1^1=0 => x=√1 &x=1]

☝️this is answer