2. Find the number of sides in a regular polygon,
if its each interior angle is :
(i) 160°
(ii) 135
1
(iii) 1 1/5 of a right angle
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Answer:
(i) Let no. of sides of regular polygon be n.
Each interior angle = 160°
∴ (n – 2)/n × 180° = 160°
180n – 360° = 160n
180n – 160n = 360°
20n = 360°
n = 18
(ii) No. of sides = n
Each interior angle = 135°
(n – 2)/n × 180° = 135°
180n – 360° = 135°
180n – 135n = 360°
45n = 360°
n = 8
(iii) No. of sides = n
Each interior angle = 1.1/5 right angles
= 6/5 × 90
= 108°
∴ (n – 2)/n × 180° = 108°
180n – 360° = 108n
180n – 108n = 360°
72n = 360°
n = 5
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