2. Find the number of sides of a polygon if
the sum of the interior angles is
a) 10 right angles
b) 720
c) 1620
d) 540°
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Answered by
10
Answer:
we know that
sum of interior angles of a polygon =(n-2)×180
let n =no . of sides in a polygon
a)
given , interior angles sum = 10 right angles
=10×90=900
(n-2)180=900
(n-2)=5
n=5+2
n=7 sides
b)
given , sum of interior anles = 720
(n-2)180=720
(n-2)=4
n=6 sides
c)
given , sum of interior angles =1620
(n-2)180=1620
(n-2) = 9
n=11 sides
d)
given, sum of interior angles = 540
(n-2)180=540
(n-2)=3
n=5 sides ..
hope it helps u a lot.☺
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Answer:
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