2) Find the number of terms in the following
a) 1+2+3+………= 1275
b) 1+4+7+………= 590
Arithmetic equation
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3
Answer:
1269
572
okay.....,......
Answered by
1
+x = 590. 1,4,7,10, ...is an A.P. first term (a) = 1. common difference (d) = a2-a1. = 4-1. d = 3. i ) Let sum of 'n' terms= Sn. S_{n}=\fr
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