Question

2) Find the perimeter of a sector of a circle of its measure is 90° and radius is 7 cm.​

Answer 1

$\mathfrak{Solution}$

Given :-

∅ = 90 °

Radius = r =  7 cm

∴ Perimeter of the sector of a circle =  $\bold{\frac{\theta}{360} \times 2\pi r + 2r}$

$\bold{= \frac{90}{360} \times 2 \times \frac{22}{7} \times 7 + 2\times7 }cm\\\\\bold{= \frac{1\times2\times22+14}{4}} cm\\\\\bold{=\frac{22+14}{2} } cm$

= 11 + 14 cm = 25 cm

$\fbox{\huge\text{Perimeter \ of \ the \ sector \ of \ a \ circle = 25 cm }}$  

$\Huge\text{Hope \ it \ will \ help \ you}$

Answer 2

Answer:

25cm

Explanation:

hope this helped you..☺