Question

2. Find the perimeter of a square park, whose area is 625 sq. m. 3 Side of a square is 12 cm. Find its area in sq. cm.​

Answer 1

Answer:

2.100

3.144

Step-by-step explanation:

2.625=a×a

a=√625

a=25

perimeter=4×a

=4×25

=100

3.area of the square=a×a

=12×12

=144

Answer 2

1) To find : perimeter of square

  Given : area of square is $625\ cm ^{2}$ .

  Solution :

• We know that all four sides of square are equal .

• If ' $a$ ' is the side of square then perimeter of square is given by,
• Area of square $= a^{2}$

                           $625 = a^{2} \\a = 25\ cm$

• Now , side of square is $25\ cm$  .

• Therefore, by substituting the value in following formula we find perimeter.

       Perimeter of square = $4a$

                                         $= 4\times 25 \\= 100\ cm$

Hence, perimeter of square is $100\ cm$ .

2) To find  : area of square .  

   Given : side of square is $12\ cm$

   Solution :

• If ' $a$ ' is the side of square then area of square is given by,
• Area of square = $a^{2}$

• Therefore, by substituting the value in following formula we find area.

       Area of square = $( 12)^{2}$

                                $= 144\ cm^{2}$  

Hence , area of square is $144\ cm^{2}$   .