Math, asked by rohanyadav4072, 5 months ago

2. Find the perimeter of each figure. (All lines meet at right angles.)​

Answers

Answered by Mxddie
3

Answer:

All segments of the polygon meet at right angles (90 degrees). The length of segment AB¯¯¯¯¯¯¯¯ is 10. The length of segment BC¯¯¯¯¯¯¯¯ is 8. The length of segment DE¯¯¯¯¯¯¯¯ is 3. The length of segment GH¯¯¯¯¯¯¯¯ is 2.

Find the perimeter of the polygon.

Correct answer:

46

Step-by-step explanation:

Answered by kirtisingh01
0

Answer:

Perimeter: The sum of all sides of a figure or a shape is known as the perimeter of that shape. e.g let a shape have five sides of length 5m, 6m, 4m, 7m, 4m, respectively, so the perimeter of that shape will be                         5+6+4+7+4 = 26m.    

Step-by-step explanation:

There are lots of shapes but some shapes have unique characteristics so that's why there are formulas for the perimeter of these shapes. e.g

Square:

  • Square having all sides same,
  • The formula for perimeter = 4 × sides.

Rectangle:

  • Rectangle has parallel sides equal,
  • The formula for perimeter = 2 × ( l + b )

Circle:

  • The Circle has fully curved sides
  • The formula for perimeter = r

There are many shapes in which all lines meats at right angles some are -Figure 1: Square of side 4m

              Perimeter = 4 × sides.

                               = 4 × 4m

                                = 16m

Figure 2: Length of rectangle = 5m

              Breadth of rectangle = 6m

              Perimeter = 2× ( l + b )

                                = 2 × ( 5 + 6 )

                                = 2 × 11

                                = 22m

Figure 3: Figure 3 is given in diagram

               Sides of figure 3 are = 12m, 6m, 10m, 5m, 5m, 10m, 6m, 12m

               Perimeter = Sum of all sides

                                 = 12m+ 6m+ 10m+ 5m+ 5m+ 10m+ 6m+ 12m

                                 =  66m

For more information see:

https://brainly.in/question/8740837

https://brainly.in/question/31620622

Attachments:
Similar questions