Question

(2) Find the perimeter of the rectangle whose length is 8cm
and a diagonal is, 10 cm,​

Answer 1

Answer:

breadth =10²-8²

100-64

√36

=6

breadth =6

area 8×6

48m²

Step-by-step explanation:

please marks as branilist

Answer 2

Answer:l=8 and diagonal(d)= 10

Using Pythagoras theorem

Breadth (b) = (10^2-8^2)^(1/2) = 6

Now,

perimeter = 2(l+b) = 2(8+6) =28

Step-by-step explanation: