Math, asked by sasmita1977, 7 months ago

2. Find the point A (x, y) when C divides AB in the ratio 2:3. Points B and C are given as
(-5, 8) and (3,6).​

Answers

Answered by DevendraLal
39

Given:

C divides AB in the ratio 2:3

Points B and C are (-5, 8) and (3,6).​

To find:

The coordinates of point A

Solution:

Let the coordinate of A (a,b)

We will use the section formula to get the coordinate of A which is given as:

(x,y) = (mx2+nx1/(m+n), my2+ny1/(m+n))

according to the question:

  • (3,6) = (2.(-5)+3a/(3+2), 2.8+3.b/(3+2))
  • (3,6) = (-10+3a/5, 16+3.b/5)

on comparing we get:

3 = -10+3a/5

  • -10+3a = 15
  • 3a = 15+10
  • 3a = 25
  • a = 25/3

6 = 16+3b/5

  • 16+3b = 30
  • 3b = 30-16
  • 3b = 14
  • b = 14/3

So the coordiantes of A are (25/3, 14/3)

Answered by amitnrw
5

Given :  C divides AB in the ratio 2:3.Points B and C are given as (-5,8) and (3,6)

To Find : point A(x,y)

Solution:

A  (x,y)

B   (-5,8)

C  (3,6)

C divides AB  in 2:3 ratio

=> Cx = (2Bx + 3Ax)/(2 + 3)

  Cy = (2By + 3Ay)/(2 + 3)  

Cx = (2Bx + 3Ax)/(2 + 3)

=> 3  = ( 2 *(-5) + 3x) /5

=>15 = -10  + 3x

=> 3x = 25

=> x = 25/3

 Cy = (2By + 3Ay)/(2 + 3)  

=> 6  = ( 2 *8 + 3y) /5

=>30 = 16  + 3y

=> 3y = 14

=> y = 14/3

point A(x,y)  = ( 25/3 , 14/3)

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