2. Find the quadratic polynomial whose zeroes are 3-√3/5 and 3+√3/5
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Answer:
x²-6x+42/5
Step-by-step explanation:
α=3-√3/5 and β=3+√3/5
Sum of zeroes =α+β
=3-√3/5+3+√3/5
=6
Product of zeroes =αβ
=(3-√3/5)(3+√3/5)
=3(3+√3/5)-√3/5(3+√3/5)
=9+3√3/5-3√3/5-3/25
=9-3/5
=45-3/5
=42/5
Required quadratic polynomial-
x²-(α+β)x+αβ
=x²-(6)x+(42/5)
=x²-6x+42/5
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