Question

2. Find the quadratic polynomial whose zeroes are 3-√3/5 and 3+√3/5
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Answer 1

Answer:

x²-6x+42/5

Step-by-step explanation:

α=3-√3/5 and β=3+√3/5

Sum of zeroes =α+β

=3-√3/5+3+√3/5

=6

Product of zeroes =αβ

=(3-√3/5)(3+√3/5)

=3(3+√3/5)-√3/5(3+√3/5)

=9+3√3/5-3√3/5-3/25

=9-3/5

=45-3/5

=42/5

Required quadratic polynomial-

x²-(α+β)x+αβ

=x²-(6)x+(42/5)

=x²-6x+42/5