Question

2. Find the quadratic polynomial whose zeros are: 6 and -3
(a) X2+3x+6 (b) x2-3x-18 (c) x2-3x+18 (d) x2+3x-6​

Answer 1

Answer:

b

Step-by-step explanation:

X^2 - (Sum of zeroes)X + (product of Zeroes)

X2 - 3X - 18

this is the required polynomial

Answer 2

Answer:

b

Step-by-step explanation:

ax^2+bx+c

sum of the roots =-b/a

x^2-3x-18=x^2-6x+3x-18=x(x+3)-6(x+3)=(x-6)(x+3)

Hence the roots of this quadratic is -3,6