Question

2. Find the remainder, if p(x) is divided by g(x) using long division method, and verify the
result by remainder theorem
P(x) = x3-4x²+x+6, g(x) = x-3​

Answer 1

Answer:

Step-by-step explanation:

P(x) = x³-4x²+x+6

g(x) = x-3

If we divide P(x) by g(x)

we get remainder as zero and the quotient will be x²-x-2

By remainder theorem,

x³-4x²+x+6 = (x²-x-2)(x-3)

                  =(x³-x²-2x-3x²+3x+6)

                  =(x³-4x²+x+6)