2 Find the remainder when x^3-ax ^2 + 6 x - a is
divided by x - a
Answers
Answered by
1
Answer:
So, by the Remainder Theorem, 2a3+5a is the remainder when x3+ax2+6x−a is divided by x−a.
Step-by-step explanation:
Correct option is
A
a
C
5a
Here, p(x)=x3+ax2+6x−a, and the zero of x−a is a
So, p(a)=a3+a×a2+6×a−a
=2a3+5a
So, by the Remainder Theorem, 2a3+5a is the remainder when x3+ax2+6x−a is divided by x−a.
Answered by
1
Step-by-step explanation:
remainder=0 and remaining. explanation as shown in attachment
Attachments:
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