Question

2. Find the roots by factorisation
2x²+x-6=0​

Answer 1

Answer:

(3/2,-2)

Step-by-step explanation:

2x²+x-6=0

2x²+4x-3x-6=0

2x(x+2) -3(x+2)=0

(2x-3)(x+2)=0

Thus,

(2x-3) = 0 or (x+2)=0

2x=3 or x=-2

x= 3/2 or x= -2

Answer 2

Answer:

$</p><p></p><p>The \: given \: \: quadratic \: equation \: is \\ 2x {}^{2} +x−6=0</p><p></p><p> \\ 2x {}^{2} +4x−3x−6=0</p><p></p><p>\\ 2x(x+2)−3(x+2)=0</p><p></p><p> \\ </p><p>(2x−3)(x+2)=0</p><p></p><p> \\ x=−2 \frac{3}{2} \\ \\ plz \: mark \: me \: as \: brainlist</p><p></p><p></p><p></p><p>$