Question

2)Find the side and perimeter of a square whose diagonal is 10 cm​

Answer 1

$side = 5\sqrt{2} cm$

$perimeter = 4 \times 5\sqrt{2} cm$

Answer 2

Answer :

We know that ,

Diagonal of a square = s√2

where s stand for side

Given is that ,

= 10 = √2 × s

$\sf{\longrightarrow\:\dfrac{10}{\sqrt{2}}\:=\:s}$

$\sf{\boxed{\longrightarrow\:Side\:=\:\dfrac{10}{\sqrt{2}}}$

Perimeter of a square = 4s

where s stand for side

= Perimeter of square = 4 × $\sf\dfrac{10}{\sqrt{2}}$

= Perimeter of square = $\sf\dfrac{40}{\sqrt{2}}$

= Perimeter of square = $\sf\:20\sqrt{2}$