2. Find the smallest number by which each of the following numbers must be multiplied
to obtain a perfect cube.
(i) 243
(ii) 256
(i) 72
(iv) 675
(v) 100
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(i) 243 (ii) 256 (iii) 72 (iv) 675 (v) 100. The prime factor 3 is not a group of three. ∴ 243 is not a perfect cube. Thus, the smallest required number to multipkly 243 to make it a perfect cube is 3.
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