Math, asked by singhrinku313670, 9 hours ago

2. Find the smallest number by which each of the following numbers must be multiplied to obtain a perfect cube. (i) 12 (ii) 50 (iii) 24 (iv) 200 (v) 1121 (vi) 10000 (vii) 1323 (viii) 675 (ix) 968 (x) 142884​

Answers

Answered by lounilcarillo511
0

Answer:

(i) 18 (ii) 20 (iii) 9 (iv) 5 (v) 1256641 (vi) 100 (vii) 7 (viii) 5 (ix) 11 (x) 14

Step-by-step explanation:

Using prime factorization, I found the smallest numbers needed to make the numbers in your question perfect cube numbers. Hope this helps.

Answered by binodrongphar2015
0

Answer:

Step-by-step explanation:

question no. (3) { 24}

solution = 24

using the prime factorisation method we get 2*2*2*3

since the factors of 3 in 24 is not in a group of 3, it is not a perfect cube.

so, we multiply 24 by 3*3.

also, the smallest number = 3*3

                                           = 9//.

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