Math, asked by mohammadrihanans, 3 months ago

2. Find the smallest number which when divided by 35, 50, 80 leaves remainder 9 in each case

Answers

Answered by nareshyadav1268655

7

Answer:

35=5×7

50=2×5×5

80=2×2×2×2×5

L.C.M.=2×2×2×2×5×5×7

=2800

smallest number =2800+9

2809

Answered by tejsingh8475

0

Answer:

2809

Step-by-step explanation:

lcm then plus the remainder

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