2. Find the smallest number which when divided by 35, 50, 80 leaves remainder 9 in each case
Answers
Answered by
7
Answer:
35=5×7
50=2×5×5
80=2×2×2×2×5
L.C.M.=2×2×2×2×5×5×7
=2800
smallest number =2800+9
2809
Answered by
0
Answer:
2809
Step-by-step explanation:
lcm then plus the remainder
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