Question

2. Find the square root of 49x²y4
3. Find the value of (2° +13)(51-30)
4. Find the value of -27-(-35)​

Answer 1

Answer:

2.7xy^2

3. 294

4. 8

Step-by-step explanation:

2.

$\sqrt{49 {x}^{2} {y}^{4} }$

=7xy^4

3. 2°=1

so, the answer is (1+13)(51-30)=14 × 21=294

4.(-27)-(-35)= (-27)+35=35-27=8