Question

2.
Find the sum of all Natural numbers less than 100 which are divisible by 6.

Answer 1

Step-by-step explanation:

6+12+18+24+30+36+42+48+54+60+66+72+78+84+90+96=916

Answer 2

Answer:

6,12,18,96.....

first term or a=6

d=a2-a1= 12-6=6

nth term= 96

a+(n-1) d=96

6+(n-1) 6= 96

n-1=90/6

n=16

sum= n/2(a+nth term)

= 16/2(6+96)

= 8*102

= 816

hope it helps...

mark me brainliest plzzz....