Question

2.
Find the
the equation of circle which is co-axial
co-axial with the
the circles
x2 + y2 - 8x+4 = 0, r? + y2 +6x+4 = 0 and x2 + y2 -11x + 4 = 0 and
touches the line 3 x - 4y= 15.​

Answer 1

Step-by-step explanation:

Circle touches internally

C1(0,0):r1=2

C2:(−3,−4);r2=7

C1C2=∣r1−r2∣

S1−S2=0 ⇒ equation of common tangent

6x+8y−20=0

3x+4y=10

(6,−2) satisfies the equation.