Question

2.
Find the total surface area of the cylinder having the following dimensions.
Radius of base = 35 cm and height = 2.5 m.​

Answer 1

${\bigstar}$GIVEN${\bigstar}$

CYLINDER:

• Radius (r) = 35cm
• height (h) = 2.5cm

${\bigstar}$SOLUTION${\bigstar}$

☞CSA of a cylinder

☞2 π r h cm²

☞2 × $\frac{22}{7}$× 35 × 2.5 cm²

☞44 × 5 × 2.5

☞ $\boxed{\sf{ 550cm² }}$

☞TSA of a cylinder

☞2πr (h+r) cm²

☞2 × $\frac{22}{7}$× 35 ( 2.5 + 35)

☞44 × 5 (37.5)

☞$\boxed{\sf{ 8250cm² }}$

◆ ━━━━━━━━❪✪❫━━━━━━━━ ◆

CYLINDER:

☞TSA = 2πr (h+r) sq.units

☞CSA = 2πrh sq.units

☞volume = πr² h cu.units

Answer 2

• GIVEN:-

Radius of base = 35 cm

Height = 2.5 m.

• To Find:-

Total surface area of the cylinder.

• SOLUTION:-

Radius is given in cm so we have to convert it in m.

1 m = 100 cm

1 cm = 1/100 cm

35 cm = 35/100 cm

So, radius = 0.35 m.

We know that,

$\large\boxed{\sf{TSA=2πr(h+r)}}$

where,

r = radius

h = height

π = 22/7 or 3.14

Putting the values,

$\large\Rightarrow{\sf{TSA=2πr(h+r)}}$

$\large\Rightarrow{\sf{TSA=2\times3.14\times0.35(2.5+0.35)}}$

$\large\Rightarrow{\sf{TSA=2\times3.14\times0.35\times2.85}}$

$\large\Rightarrow{\sf{TSA=6.26\:{m}^{2}}}$

$\large{\red{\underline{\boxed{\therefore{\sf{\red{Total\:surface\:area\:=6.3\:{m}^{2}}}}}}}}$

• EXPLORE MORE:-

• TSA = 2πr (h+r) square units

• CSA = 2πrh square units

• volume = πr² h cube units