Math, asked by brotherssquad1998, 6 months ago


2. Find the value of 'a' so that (-2) is a root of 2x2-x+ a = 0
between 2 and 2​

Answers

Answered by satyavenijoga62453
0

Answer:

-10

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Answered by aryan073
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Q1) Find the values of 'a'so that (-2) is a roots of 2x²-x+a=0

 \:  \:  \underline{ \boxed{ \sf{ \color{magenta} \: answer  \to}}}

 \:  \:  \implies \bf{2 {x}^{2}   - x + a = 0}

 \:  \:  \implies \displaystyle \tt{2 {( - 2)}^{2}  - ( - 2) + a = 0}

 \:  \implies \displaystyle \tt{8  + 2 + a = 0}

 \:  \:  \implies \displaystyle \bf{a =  - 10}

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