Question

2.Find the value of below algebriac expression for x=2,y=-1 and z=2
i. 4x²−3y²+5z²
ii. 3x³−2x(4yz+5x²)
iii. 1−4x(yz+3xy)

Answer 1

Answer:

2.

x=2

y=1

z=2

Step-by-step explanation:

I) 4X^2-3y^2+5Z^2

=4(2)^2-3(1)^2+5(2)^2

=4(4)-3(1)+5(4)

=16-3+20

= 33

ii) 3x^3-2x(4yz+5x^2)

= 3(2)^3-2(2)[4(1)(2)+5(2)^2]

= 3(8)-4[8+5(4)]

=24-4[8+20]

=24- 4(28)

=24-112

= -88

iii) 1-4x(yz+3xy)

= 1- 4(2)[(1)(2)+3(2)(1)]

=1-8[2+6]

=1-8(8)

=1-64

= -63