Question

2 Find the value of :-

i) 2^-3.
ii)1/3^-3​

Answer 1

Answer:

Step-by-step explanation:

solution

(i)  $2^{-3}$ = $\frac{1}{2^{3} }$

$\frac{1}{2^{3} }$ = $\frac{1}{8}$

$\frac{1}{8}$ = $8^{-1}$

(ii) $\frac{1}{3^{-3} }$ = 1 ÷ $\frac{1}{3^{3} }$

1 ÷ $\frac{1}{3^{3} }$ = 1 ÷ $\frac{1}{9}$

1 ÷ $\frac{1}{9}$ = 1 x $\frac{9}{1}$

= 9

in summery

$2^{-3}$ = $\frac{1}{8}$ or $8^{-1}$

1/$3^{-3}$ = 9

Answer 2

Answer:

first one

=1/8

secound one