Question

2. Find the value of k (a) 2^4x (0.5)^-3 = 2^k

Answer 1

${2}^{4} \times {0.5}^{ - 3} = {2}^{k}$

${2}^{4} \times {( \frac{1}{2}) }^{ - 3} = {2}^{k}$

${2}^{4} \times {2}^{ 3} = {2}^{k}$

Adding exponents when base are same,

${2}^{7} = {2}^{k}$

Equating exponents when base are same,

=> k = 7

Hence, the magnitude of k for which given equation turns true is k=7.

Answer 2

Answer:

the ans is 7

Step-by-step explanation: