Question

2. Find the value of 'k' for which x=3 is a solution of the quadratic equation
. (k+2) x² – kx+6=0
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Answer 1

$\bold\red{\underline{\underline{Answer:}}}$

$\bold\green{\underline{\underline{Solution}}}$

x=3 is one of the root of quadratic equation ...given

Substituting x=3 in given equation

$\bold{(k+2)3^{2}-3k+6=0}$

$\bold{9k+18-3k+6=0}$

$\bold{6k+24=0}$

$\bold{6k=-24}$

$\bold{k=\frac{-24}{6}}$

$\bold{k=-4}$

The value of k is -4.