Question

2) Find the value of k such that the polynomial
x^2-(k+6)x+2( 2k-1) has sum of its
zeroes equal to half of their product
​

Answer 1

Answer:

hope this will helpyou

Answer 2

Answer:

k=7

Step-by-step explanation:

• given
• polynomial sum=-b/a=(k+6)/1
• product of polynomial

=c/a=2(2k-1)/1

by given data ..

k+6=2(2k-1)/2

k+6=2k-1

k=7