Question

2) Find the value of K, when the distance between the points(3,2k) and (4,1) is √10 units.

Answer 1

Step-by-step explanation:

By distance formula,

√{ (4-3)^2 + (1-2k)^2 } = √10 units

Squaring both sides.

{4-3) ^2 +(1-2k) ^2} = 10

1+1+4k^2 - 4k =10

4k^2-4k -8=0

k^2 -k -2 = 0 (divide by 2)

k^2 -2k +k -2 =0

k(k-2) +1(k-2) =0

(k-2) (k+1)=0

So,

k=2 or -1