Question

2.
Find the value of p for which the quadratic equation
x(x-4) +p=0 has real roots​

Answer 1

Answer:

p=4

Step-by-step explanation:

, , , ,,, ,,,,,,,,,,,,,,,,,,,,

Answer 2

Answer:

p = 4

Step-by-step explanation:

x(x -4) + p = 0

x² - 4x + p = 0

d = b² - 4ac

given eq has real roots.

so , d = 0

0 = (-4)² - 4 × 1 × p

0 = 16 - 4p

16 = 4p

16/4 = p

4 = p