2. Find the value of the determinant | 0 6 2 5|.
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Answer:
The value of the determinant
∣
∣
∣
∣
∣
∣
3
6
5
3
−4
2
2
∣
∣
∣
∣
∣
∣
is
(2×3
6
)−(5
3
×(−4
2
))
=6
6
−(−20
6
)
=6
6
+20
6
=26
6
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