2. Find the value(s) of k, if the quadratic equation 3x2 - k 3 x+ 4= 0 has equal roots.
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Answered by
1
D=b²-4ac
since the equation have equal roots so D=0
0=(k3)² - 4 (3) (4)
0=9k²-48
48=9k²
k²=48/9
k=√48/9
k=±4√3/3
since the equation have equal roots so D=0
0=(k3)² - 4 (3) (4)
0=9k²-48
48=9k²
k²=48/9
k=√48/9
k=±4√3/3
aiswaryalakshmibinoy:
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Answered by
0
Frist question is wrong questions is 3x²-3kx+4=0
Frist write b²-4ac
b=-3k
a=3
c=4
(3k)²=4×3×4
9k²=12×4
9k²=48
k²=48/9
k=√48/9
k=±4/3√3
Frist write b²-4ac
b=-3k
a=3
c=4
(3k)²=4×3×4
9k²=12×4
9k²=48
k²=48/9
k=√48/9
k=±4/3√3
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