Question

2. Find the values of :
(i) 2 tan245° + cos230° – sin’60°
(ii) cos290° + sin 30° + tan 45°
(iii) sin 30°.cos 45º + sin 45º.cos 30°
(iv) sin230 + cos²60 + tan-45°
(v) 2 sin 45º.cos 45º

Answer 1

Answer:

yavshsooaoakakakan sjakoakansbzjapkabsudosnjsspsnbsiaj ok bye

Answer 2

Answer:

1) 2 tan2 45° + cos2 30° – sin2 60°

  We know

tan45° = 1

cos30⁰ = root3/2

sin60⁰ = root3/2

by substitute in the given equation

2(1)² + (root3/2)² – (root3/2)² = 2

in the image