Question

2. Find the values of k for each of the following quadratic equations, so that they have two
equal roots.
(1) 2xsquare + kx + 3 = 0
(ii) kx (x - 2) +6=0​

Answer 1

Solution

To have equal roots, D equal to 0 [D = 0].

(i) 2x² + kx + 3

→ D = b² - 4ac = 0

→ k² - 4(2)(3) = 0

→ k² = 24

→ k = √24

→ k = ± 2√6

Hence value of k can be +2√6 and - 2√6.

(ii) kx(x - 2) + 6 = 0

→ kx² - 2kx + 6 = 0

→ (- 2k)² - 4(k)(6) = 0

→ 4k² -24k = 0

→4k(k - 6) = 0

→ k = 0 and 6 [Due to two possibilities]

Hence value of k can be 0 and 6.

Answer 2

Answer:

hope this helps.........