Question

2) Find the values of x and y observing the rectangular shape.
4(x+2) + 3(y+2)
7
5x+4y
20​

Answer 1

Answer:

It is given 

5x−4y=20

Now by substituting (4,0) in the place of x and y We know that the LHS

=5x−4y

=5(4)−4(0)

 On further calculation 

=20

 =RHS

 Therefore (4,0) is the solution of 5x−4y=20

 (ii) It is given 

5x−4y=20

 Now by substituting (0,5) in the place of x and y We know that the LHS

 =5x−4y

 =5(0)−4(5)

 On further calculation 

 =−20

 =RHS

 Therefore (−2,25) in the place of x and y we know that the LHS 

 =5x−4y

=5(−2)−4(25)

 On further calculation 

 =−10−10

 =−20

 =RHS

 Therefore (−2,25)is not the solution of 5x - 4y = 20

 (iv) it is given

5x−4y=20

 Now by substituting (0,5) in the place of x and y We know that the LHS

=5x−4y

=5(0)−4(−5)

 Our further calculation

=20

 =RHS

 Therefore, (0,-5) is the solution of 5x−4y=20

 (v) it is given 

 5x−4y=20

 Now by substituting (2,−25) in the place of x and y we know that  the LHS

=5x−4y

 =5(2)-4 (−25

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