Math, asked by Anonymous, 1 month ago

2. Find the work done when a 25 kg weight is (i) lifted to a vertical height of 2.0 m from the ground, (ii) carried to the same place by pushing it up an inclined plane making an angle of 30° with the ground. Take g =9.8 m s-2 Ans. (i) 490 J, (ii) 490 J.


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Answers

Answered by VenomArmy
89

質問-:

。 25 kgの重りを(i)地面から垂直方向の高さ2.0 mまで持ち上げ、(ii)地面に対して30°の角度をなす傾斜面を押し上げて同じ場所に運ぶときに行われる作業を見つけます。g =9.8ms²を取る

説明-:

(1)

私達はことを知っています-:

tW = mgh

値を置く-:

→W = 25x9.8×2

→W = 50×9.8

W

490 J

(11)

体が角度を作っている場合

ここで作業が完了しました-:

W = F Scos

値を置く-:

→W = 25x9.8×2cos0°

→W = 25x9.8x2

W =490J

Answered by sinharay1
24

sry can't answer. coz I don't know Japanese

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