Question

2) Find the zero of the quadratic polynomial 3x2 - 27​

Answer 1

Solution :

= 3x² - 27 = 0

= 3x² = 27

= x² = 27/3

= x² = 9

= x = √9

= x = 3

Now,

= x = +3 & x = -3 .

Thus, the zeroes of the polynomial.

Answer 2

Answer:

$\underline{\purple{\ddot{\Mathsdude}}}$

♧♧To prove :-

• Zeroes of the polynomial.

♧♧Explanation :-

• 3x^2-27=0

• 3x^2 =27

• x^2 =27/3

• x^2 = 9

• x = root of 9

• x=3

Therefore, x=+3 , x= -3 are the zeroes of the polynomial.

♧♧Hope it helps u mate.

♧♧Thank you .