Question

2. Find the zeroes of the quadratic polynomialy-3y+2.​

Answer 1

Answer:

The graph of −3y+x−12=0 intersect the x-axis at (12,0).

Hence the zero of −3y+x−12=0 is (12,0) as it intersects at x-axis at (12,0).

Step-by-step explanation:

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Answer 2

EXPLANATION.

Quadratic polynomial.

⇒ y² - 3y + 2.

As we know that,

Factorizes this equation into middle term splits, we get.

⇒ y² - 2y - y + 2 = 0.

⇒ y(y - 2) - 1(y - 2) = 0.

⇒ (y - 1)(y - 2) = 0.

⇒ y = 1  and  y = 2.

                                                                                                                   

MORE INFORMATION.

Nature of the roots of the quadratic expression.

(1) = Real and unequal, if b² - 4ac > 0.

(2) = Rational and different, if b² - 4ac is a perfect square.

(3) = Real and equal, if b² - 4ac = 0.

(4) = If D < 0 Roots are imaginary and unequal Or complex conjugate.