Question

2) Find the zeros of x2 + 5x+6.​

Answer 1

Answer:

${x}^{2} + 5x + 6 \\ \\ = {x}^{2} + (3 + 2)x + 6 \\ \\ = {x}^{2} + 3x + 2x +6 \\ \\ = x(x + 3) + 2(x + 3) \\ \\ = (x + 3)(x + 2) \\ \\ so \: zeroes \: would \: be \: ( - 3) \: and \: ( - 2)$

hope this much helps uh ❣️

Answer 2

$\huge\bf\underline{\red{Y}\green{o}\orange{U}\pink{r}\:\red{A}\purple{n}\blue{S}\orange{w}\red{E}\purple{r}}$

${x}^{2} + 5x + 6 \\ \\ = {x}^{2} + (3 + 2)x + 6 \\ \\ = {x}^{2} + 3x + 2x + 6 \\ \\ = x(x + 3) + 2(x + 3) \\ \\ = (x + 3)(x + 2) \\ \\ zeroes \: of \: the \: polynomial \: \\ \\ = - 2 \: or \: - 3$

✧ done ✧