2. Find two numbers nearest to 8888888 which are exactly divisible by 2915
Answers
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Explanation:
Solution:
Given problem is to find nearest number,
= 8888888/2915
quotient = 3049
remainder= 1053
Now,
2915-1053 = 1862
8888888+1862 = 8890750
8888888-1053 = 8887835
Two numbers nearest to 8888888 which are exactly divisible by 2915 is 8887835 and 8890750
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