Question

2. Find two numbers nearest to 8888888 which are exactly divisible by 2915​

Answer 1

Explanation:

Solution:

Given problem is to find nearest number,

= 8888888/2915

quotient = 3049

remainder= 1053

Now,

2915-1053 = 1862

8888888+1862 = 8890750

8888888-1053 = 8887835

Two numbers nearest to 8888888 which are exactly divisible by 2915 is 8887835 and 8890750